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【java】368. 最大整除子集---使用动态规划,快速解决子问题!!!
阅读量:318 次
发布时间:2019-03-04

本文共 870 字,大约阅读时间需要 2 分钟。

给你一个由 无重复 正整数组成的集合 nums ,请你找出并返回其中最大的整除子集 answer ,子集中每一元素对 (answer[i], answer[j]) 都应当满足:

answer[i] % answer[j] == 0 ,或
answer[j] % answer[i] == 0
如果存在多个有效解子集,返回其中任何一个均可。

示例 1:

输入:nums = [1,2,3]

输出:[1,2]
解释:[1,3] 也会被视为正确答案。
示例 2:

输入:nums = [1,2,4,8]

输出:[1,2,4,8]

提示:

1 <= nums.length <= 1000

1 <= nums[i] <= 2 * 109
nums 中的所有整数 互不相同
在这里插入图片描述

代码:public List
largestDivisibleSubset(int[] nums) { List
list=new ArrayList
(); if(nums.length==0) { return list; } Arrays.sort(nums); //记录该元素整除元素的个数 int []dp=new int[nums.length]; //记录该元素整除最近的下一个元素的下标 int []index=new int[nums.length]; Arrays.fill(index,-1); int a=0; for(int i=0;i
dp[i]) { dp[i]++; index[i]=j; if(dp[i]>dp[a]) { a=i; } } } } while(a!=-1) { list.add(nums[a]); a=index[a]; } return list; }

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